A bus moves with a velocity of 36km/h.The driver apply brakes & bus stop after travelling a distance of 10m.?

Question

Calculate the deceleration and the time taken by bus to come to rest.

Please show full calculation.

Answer 1

v=vi-a*t (eq.1)

v=final velocity (om/s cause it stops)

vi=initial velocity (36km/h=36000m/3600s=10m/s)

t=time to stop

d=vi*t-.5*a*t^2 (eq.2)

d=distance (10m)

solve eq.1 for t

t=10/a (eq.3)

substitute t to eq.2

10=10*(10/a)-.5*a*(10/a)^2

solve for a and substitute to eq.3 to find t

Answer 2

the previos answer is correct