A car goes 145 km west and then 85 km southwest. What is the displacement of the car from the point of origin?

Question

:( Help, please? I tried drawing vectors but I couldn't find ANYTHING

Answer 1

Yes, there are no angles provided but you can still find the resultant displacment and the actual angle

Use Pythagoreom's theorem, and you will get 168 km.

If you're really curious about its actual angle, just find its tangent which is 38 degrees. Thus the displacement travels at 168 km making an angle of 52 degrees.  

Answer 2

the angle formed between the two vectors is 45. So using triangle law the resultant vector is [(145^2)+(85^2)+145*85*cos45]. By solving this the answer is coming to be 192.26 km.Thats the displacement of the car.

Answer 3

http://img152.imageshack.us/img152/7688/...

Answer 4

Draw it

You get a right triangle

the displacement is the hypotenuse which is equal to sqrt(the square of 2 other sides) ====> Pythagoras

the displacement = sqrt([145^2]+[85^2]) = 168,077 Km approximately 168 Km

Answer 5

The angle when the car goes west is 180 (negative direction of x axis), and when it goes southwest it is 225. Does that help?