A car has an acceleration of 8m/s2? if is final velocity is 24m/s2 how far does it travel during the period?

Question

a little bit of help from a big apple heart...> thanks

Answer 1

v^2=u^2+2as

8^2=0^2+2*10*s

64=0+20*s

64=20*s

64/20=s

3.2m=s

Answer 2

You mean final velocity is 24 m/s

if the car started moving from rest

use

v(f)^2 = v(0)^2 + 2ax

where

v(f) is the final velocity

v(0) is the begining velocity

a is acceleration

x is the distance

576 = 16 x

so x = 36 meter

Answer 3

vf - final velocity = 24 m/s

vo - initial velocity = 0 m/s

a - acceleration = 8 m/s^2

t - time

x - change in distance

vf=vo + at

at = vf - vo

t = (vf - vo)/a

t = (24-0)/8 = 3 s

x = v0*t + 1/2 at^2

x = 0 + 1/2 * (8*3^2) = 1/2 * (8*9) = 36 m

Answer 4

Provided the initial velocity is zero.

first calculate its period:

v = u + at

24 = (0) + 8(t)

8t = 24

t = 3secs

now calculate its distance travelled using this equation:

s = ut + ½at²

s = (0 * 3) + ½(8)(3²)

s = 36m

so the distance is 36m

hope this helps^_^