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A circle of area 27pie^2 must have a radius what is the answer?

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A circle of area 27pie^2 must have a radius what is the answer?

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  1. Area = (pi) r^2

    27(pi)^2 = (pi) r^2

    27(pi)=r^2

    sqrt(27(pi))= r  =sqrt ((9x3)(pi)) = 3(sqrt 3)(sqrt pi)

    3 (sqrt 3)(sqrt pi) or approx. 9.21 to three significant figures


  2. A = pi * r^2

    27pi^2 = pi * r^2

    27pi = r^2

    root(27pi) is your answer, assuming you meant 27 * (pi)^2

    If you meant (27pi)^2, then the answer is (27pi) / root(pi)

  3. 27(pi)(r)^2

    r=27

  4. Area = 27 pi^2 = pi r^2

    => r = sqrt{27pi}

           = 9.2117936829448615882474331037779

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