A cumulative chemistry question regarding vapor pressure?

Question

If 13.0 grams of CCl3F is enclosed in a 1.1 - L container, will any liquid be present?

INFO: The vapor pressure of CCl3F at 300K is 856 torr.

Answer 1

Assuming the temperature is 300 K then.

PV=nRT

856 torr x 1.1 L=n x 62.4(mmHg♦L)/(mol♦K) x 300 K

n=0.050 mol

0.050 mol x 137.5 g CCl3F/mol=6.9 g CCl3F

So we have 6.9 grams of vapor leaving us with 6.1 grams of liquid.