A current-carrying conductor is kept at right angles to the direction of a magnetic field. What happens to the

Question

force acting on the wire if the strength of the magnetic field doubles?

A. The force is doubled

B. The force is not changed.

C. The force is halved.

D. The force becomes one-fourth.

Answer 1

the formula for a current carrying conductor placed in a magnetic field is :

F=i(LBsin x)

where x is the angle between the wire and the magnetic field.

here x=90 degrees so sin x=1.

hence F=iLB.(here L is the length of the wire and B is the magnetic field)

hence F is directly proportional; to B. if B is doubled the force on the wire doubles.

hence ans is A.