Question:

A current of 15 A electroplated 50 g of hafnium metal from an aqueous solution in 2hr.

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What is the oxidation

of hafnium in the solution?

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  1. Moles Hf = 50 g / 178.5 g/mol =0.280

    2 h => 7200 seconds

    15 A means 15 Coulomb/s

    15 Coulomb/s x 7200 =  108000 Coulombs

    108000 / 96500 =  1.12 Faradays

    1.12 F / 0.280 mol = +4 (number of oxidation )

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