A current of 2.50 amps is passed through a solution of Cu(NO3)2?

Question

for 2.00 hours. What mass of copper is deposited at the cathode?

Answer 1

Cu2+ + 2e- >> Cu

2.00 h = 7200 s

2.50 x 7200 = 18000 Coulumb

18000 / 96500 = 0.187 Faradays

0.187 F ( 1 mole Cu/ 2 Faradays) = 0.0935 mole

Mass = 0.0935 mol x 63.54 g/mol =5.94 g