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A current of 5 A flowing in a resistor of value 10 kΩ (kilohms) produces what voltage drop?

by Guest56336  |  earlier

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A current of 5 A flowing in a resistor of value 10 kΩ (kilohms) produces what voltage drop?

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  1. The formula for calculating voltage is E = I * R

    A 5 A current times a 10k ohm resistor equates to a 50,000 volt drop.


  2. voltage drop = current * resistance.

                  = 5 * 10000 = 50000 volts

    so, the voltage drop is 50000 volts

  3. The numerical answer is 5 A x 10^4 ohms = 50,000 V. But the physical situation is unrealistic because the power dissipation would be I^2 R = 250 kW.

  4. You don't give enough information.

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