A curve has equation y=(x-1)(2x-3)^8. Find...?

Question

A curve has equation y=(x-1)(2x-3)^8. Find the gradient of the curve at the point where x=2

Answer 1

17

Take the derivative using the Product Rule.  Don't forget the Chain Rule for d(2x-3)/dx.

Answer 2

i think that means slope? if it does, you have to do derivative.

dy/dx=(16)(2x-3)^7(x-1)+(2x-3)^8

then plug in two

(16)(2(2)-3)^7((2)-1)+(2(2)-3)^8=17

make it a good day