A diver running 1.4 m/s dives out horizontally from the edge of a vertical cliff and 3.3 s ?

Question

later reaches the water below.

How high was the cliff?

How far from its base did the diver hit the water?

HELP ME PLEASE/ ITS A HMW QUESTION

Answer 1

Well you need to use this equation:

Delta X = (initial velocity)x(time) + (.5)x(acceleration)x(time squared)

Promise to try to learn it but the answers are:

1.The cliff is 53.4 meters tall

2.The diver lands 4.62 meters from the edge of the cliff

1.DX in vertical direction= (.5)(9.8)(3.3^2)

2.DX in horizontal direction= (1.4)(3.3)

the other side of the equation is just zero for the two problems so i left it out.