A fire hose held near the ground shoots water at a speed of 7.7 m/s.?

Question

At what angles should the nozzle point in order that the water land 2.0 m away. Only the smaller angle..... I have the larger angle as angle of 80

Answer 1

This problem can be treated as a projectile problem and the formula to be used is

R = Vo^2(sin 2A)/g

where

R = maximum horizontal distance = 2 m (given)

Vo = initial velocity = 7.7 m/sec (given)

A = angle of projection

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

Substituting appropriate values,

2 = (7.7^2)(sin 2A)/9.8

Solving for sin 2A,

sin 2A = 2(9.8)/(7.7)^2

sin 2A = 0.3306

2A = arc sin 0.3306

2A = 19.30 degrees

A = 19.3 / 2

A = 9.65 degrees