A football is kicked at ground level with a speed of 40.0 m/s at an angle of 32.0° to the horizontal?

Question

How much later does it hit the ground in seconds?

Answer 1

When it reaches it's highest point it's

vertical velocity = zero

v=40*sin(32)-g*t

or

0=40*sin(32)-9.8*t

9.8*t = 40*sin(32)

so

t= 2.163 seconds to get to the top

same time to get down

total time = 2*2.163 = 4.326 seconds

You didn't ask, but how high did the football go:

height = 40 * Sin(32) * 2.163 - 0.5 * 9.8 * 2.163 ^ 2=22.92m

ck=0.5 * 9.8 * 2.163 ^ 2=22.92m

Answer 2

depends on various factors of course

Answer 3

V(initial) = 40sin32 up

g           = 9.8 down

d(vert)    = 0

   0 = 40sin32t  - 4.9tt

   0 =  t (  40sin32 - 4.9t)

    t =0 and  t = (40sin32)/4.9

                    = 4.3 sec

Answer 4

using kinematics equation.

v=u+at

0=40sin32 - 9.81t

t= (40sin32)/9.81

note that this is the time taken to reach the top. u need to multiply the answer by 2 to include the time taken to travel back down....