Question:

A gas occupies a volume of 2.4 L at 1 atm. What volume will the gas occupy at 6 atm?

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2.5 L

2.4 L

.4 L

14.4 L

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3 ANSWERS


  1. I'm sure it's 14.4 L

    2.4 L /1 atm X 6 atm = 14.4 L


  2. The ideal gas equation is PV = nRT. From that you can derive P1V1 / T1 = P2V2 / T2. Since temperature is constant, the equation you'll use is P1V1 = P2V2. This is also known as Boyle's Law and it states that when temperature of an ideal gas is constant, the volume it will occupy will be inversely proportional to its pressure.

    Plug the values in so you get: (1)(2.4) = (6)(x)

    You want to solve for x which is the volume the gas will occupy at 6 atm. When you solve for x you should get that at constant temperature and 6 atm, the gas will occupy .4 L

  3. PV=nRT

    P1V1/nRT1=P2V2/nRT2

    so

    P1V1/T1=P2V2/T2

    or

    P1V1T2=P2V2T1

    if the temp. is constant, substitute the values and you can get the answer.

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