A glass coffee cup is at room temp..find specific heat?

Question

A 3.65 x10^2 g glass coffee cup is at room temperature, 20.0°C. It is then plunged into hot dishwater, 78.0°C. If the temperature of the cup reaches that of the dishwater, how much heat does the cup absorb? Assume the mass of the dishwater is large enough so its temperature doesn't change appreciably.

___J

i know the equation is J=cp*(.365)*(78-20)

is there something i am doing wrong?

Answer 1

specific heat glass at 20 C: .84 J/gm K

E = .84 J/gm K x 365 g x (78-20) K

E = .84 x 365 x 58 = 17780 J

.

Answer 2

You have the correct formula - assuming cp is the specific heat of the glass

so heat gain will be mass x sp ht x temp gain

= 0.365 x 10^2 x c x 58

but of course you need the sp heat of glass to finish the calculation