A golfer hits the ball with an initial velocity of 140 ft/sec and makes the angle of 31 degrees...?

Question

When does the ball hit the ground? How far from its starting point does it land? What is the maximum height of the golf ball during its flight?

Answer 1

Projectile Motion

t = vi sin Θ / g = time of flight

x = vi² sin2 Θ /g = range

y = ( vi sin Θ)² / 2g = peak height

vi = initial velocity of 140 ft/sec

Θ = launch angel of 31 degrees

g = 32 ft/sec

When does the ball hit the ground?

t = vi sin Θ / g = time of flight

t = 140 ft/sec * sin 31 = 140 * 0.515 = 72 sec

How far from its starting point does it land?

x = vi² sin2 Θ /g = range

x = 140²  * sin (2 * Θ) / 32 = 19600 * 0.88 / 32 = 540.8 ft

What is the maximum height of the golf ball during its flight?

y = ( vi sin Θ)² / 2g = peak height

y = ( 140 * sin 31)² / 2 * 32 = 72² / 64 = 81 ft