A gun shoots a shell into the air with an initial velocity of 100m/s, 60.0 degrees above the horizontal on?

Question

level ground. What are the horizontal and vertical components as functions of time?

Answer 1

horizontal=V Cos A  T = 100 Cos 60 (T)= 50 T

Vertical= V Sin A T - 1/2(g)T^2= 100 Sin 60 (T) -(1/2)(g) T^2

Answer 2

Assuming you mean components of velocity:

Horizontal component velocity = 100 *cos(60) m/s

Vertical component velocity = 100 *sin(60) - 0.5*9.8*t^2  m/s

Assuming you mean distance traveled:

Horizontal distance (range)  = 100 *cos(60)* t

Vertical distance  = [100 *sin(60)  - 0.5*9.8*t^2]*t