A legitimate Algebra honors question.?

Question

Me and my friend live 12 miles apart. We leave home at the same time and and travel toward each other. I walk at a rate of 4 miles and hour and he bicycles at 11/mph.

a) How long after we leave home will we meet? How far from home will each of us be?

b) Suppose my friend bicycles at a rate of 12 miles per hour. How much sooner will you meet? How far from home will each of you be?

In deep trouble if this doesn't get answered.

please help

Answer 1

d=rt

you:   d = d (the amount you covered)  r =4  so your distance = 4t (4 times however long)

Friend: d=12-d (the amount covered by your friend) and r =11

so to cover 12 miles is:    12 = 4t + 11t   solve for t

12 = 15t

t = 12/15 = 4/5 of an hour which is 48 min.  now take that time and plug into the related equation:

you:  d = 4(4/5 of an hour)      friend: d = 11(4/5 of an hour)

For b), change 11mph to 12: 12 = 4t + 12t and solve the same way