A little TRIG QUESTION!? ?

Question

Given the point (1, -2) on the terminal side of an angle, find the value of all six trig functions.

Answer 1

sin=(-2sqrt5)/5

cos=(sqrt5)/5

tan=-2

cot=-1/2

sec=sqrt5

csc=(-sqrt5)/2

Answer 2

so i think this is how you do it:

(1, -2) is in the IV quadrant

x=1

y= -2

find r by doing pythagorean...r =root5

then since you have x, y, and r you can find all six trig functions but plugging in the values

sin = y/r

cos = x/r

tan = y/x

sec = r/y

csc = r/x

cot = x/y

Answer 3

Given the point (1, -2) on the terminal side of an angle, find the value of all six trig functions.

mandarin..

This is special right Triangle

1,2,√3

Since the y =-2. therefore it is in the second quadrant triangle

x = 1

y =-2

h = √3

Φ = measured from x-axis to hypotenuse h

Sin Φ = y/h = -2/√3

Cos Φ = x/h = 1/√3

Tan Φ = y/x = -2/1 = -2

Cot Φ = x/y = 1/-2 = -1/2

Sec Φ = h/y = √3/-2 = -√3/2

Csc Φ = h/x = √3/1 = √3

hope this helps