A man runs 200m east and another at 400m south. What is the resultant displacement?

Question

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Answer 1

why was they running?

Answer 2

They would be 447.21359m apart.

Answer 3

650 meters. 600 + 50 because the one running east fell in the mine, it was 50m deep.

Answer 4

447.21m

Answer 5

Hard to say. The one running east fell down a mine?

Answer 6

600m away from original starting place, he never headed toward his destination again.

Answer 7

Now that's a question for the  ancient Ionian mathematician Pythagorean. We're looking for the displacement of the two runners. Pythagorean tells us "A squared + B squared = C squared."

Answer 8

Well your question isn't worded too well, I mean if the man runs 200m east his displacement is 200m and if another man runs 400m south his displacement is 400m, if you mean the same man does that then 400^2+200^2 = D^2, D =447.2136M

Answer 9

its a question of the pythagorus theorum... = a2 + b2= c2

c being the longest side.

a= 200  b= 400

200x 200 + 400 x 400 =  200,000

square root of 200,000 = c

c= 447.21

Answer 10

447.21m frm starting point on a south easterly direction

Answer 11

The displacement is the change in position from A to B (from "dis place" to "dat place". The path doesn't matter.

Draw the two vectors, 200 east and then 400 south.  You use the Pythagorean theorem (A squared plus B squared = C squared) to find the third side of the triangle.  If the problem asks for the VECTOR displacement, you need to give both distance and angle.  The angle is found by using the inverse tangent of 400/200.

Answer 12

A squared + B squared = C squared

I'm not gonna do the work for you, it's your homework.

Answer 13

displacement = x

x^2= 400^2 + 200^2

x^2 = 40000 + 160000

x = 447.2136 m