A math question involing substituion please?

Question

2b+3u=11

5b-2u=-1

Answer 1

4b + 6u = 22

15b - 6u = - 3-----ADD

19b = 19

b = 1

2 + 3u = 11

3u = 9

u = 3

u = 3 , b = 1

Answer 2

1st value of u:

2b + 3u = 11

3u = 11 - 2b

u = (11 - 2b)/3

2nd value of u:

5b - 2u = - 1

2u = 5b + 1

u = (5b + 1)/2

Value of b:

2(11 - 2b) = 3(5b + 1)

22 - 4b = 15b + 3

19b = 19

b = 1

Value of u:

= (11 - 2[1])/3

= (11 - 2)/3

= 9/3 or 3

Answer: b = 1, u = 3

Proof (1st equation):

2(1) + 3(3) = 11

2 + 9 = 11

11 = 11

Proof (2nd equation):

5(1) - 2(3) = - 1

5 - 6 = - 1

- 1 = - 1

Answer 3

2b+3u=11

5b-2u=-1

2(2b+3u=11)

3(5b-2u=-1)

  4b+6u=22

15b-6u=-3

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19b=19 => b=1

Now that we have got b , we put b(=1) in one of the equations :

--->2b+3u=11

5b-2u=-1

--->(2*1)+3u = 11

so 2+3u=11

     3u=11-2

     3u=9

and u=9/3

      u=3

**************************************...

b=1

and

u=3

Answer 4

7b+1u=10

so...

u=10-7b

5b-20+14=-1

5b=-1+6

b=1

and

u=3

Answer 5

Here's How To Do It.

2b + 3u = 11

5b - 2u = -1

So We Multiply Each of The Equations So One Of The Values In Each of The Sums Are The Same.

2b + 3u = 11 (x2)

5b - 2u = -1 (x3)

This Gives You The Following;

4b + 6u = 22

15b - 6b = -3

We Add The Two Equations Together To Get Rid Of The "b" So we get The Following;

19b = 19

So we Therefore Deduct That b =1. If B Equals One Then We Can Work Out U.

2(1) + 3u =11 and,

5(1) - 2u = -1 so,

2+ 3u = 11 and

5 -2u = -1.

We Transfer The Values Over To The Opposite Side And We Get

3u = 11 - 2 and

-2u = -1 -5

This Means That 3u = 9 and -2u = -6

So Both Equations Give An Answer Of 3 When It Comes To U

So We Deduce That:

b = 1 and

u = 3

Check; 2(1) + 3(3) = 11 Correct So It Must be True!!

Hope This Helps.