A math ratio question?

Question

A sum of money is to be divided in the persons, X,Y AND Z in the ratio 10:7:5. If Y gets 14$ more than Z, what is the share of X and what is the total sum of money???

I know how to solve these ratio questions but i'm stuck on this one. Can anybody help please?

Answer 1

So we have these two equations:

x/10 = y/7 = z/5

y = z+14

Combining:

z/5 = (z+14)/7

z/5 = z/7 + 2

z/5-z/7 = 2

2z/35=2

z=35

They want x, so:

x/10=z/5

x/10=35/5=7

x=70

If we find y, we get the total:

y/7=z/5

y/7=35/5=7

y=49

So x=70, y=49, z=35

The total is $154

Answer 2

y is 7

z is 5

the difference is 2

therefore $14 = 2

thus 1 = $7

then, 10 x 7 = $70

7 x 7 = $49

and 5 x 7 = $35

oh and total = $154

Answer 3

X = $70

Y= $49

Z= $35

Total will be $154

Answer 4

X:Y:Z is 10:7:5   Y gets $14 more than Z, so we have X:Z+14:Z

So we can put that as a two ratios equalling each other 7/5 = (z+14)/z

Cross multiply  7z=5z+70  Solve for Z  35  Y is 49, solve for X

10/7 = x/49

Solve for X  X = 70

For those of you giving me thumbs down, I sort of figured the person answering the question could add up X, Y, and Z to find the total sum...