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A mixture of H2(g) and Cl2(g) exerts a total pressure of 2.50 atm if the mole fraction of H2 is 0.490 what is

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the partial pressure in atm of H2? if you can explain the procedure I appreciate it

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  1. P(H2) = X(H2) x P(total)

    P(H2) = 0.490 x 2.50 atm = 1.23 atm

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