A mixture of He , Ne and Ar has a total pressure of 0.80 atm and is found to contain 0.55 mol He 0.94 mol Ne

Question

and 0.35 mol Ar what is the partial pressure in atm of each gas?

I am so confused please help me out with the procedure

Answer 1

Raoult's law states that the partial pressure of a gas in a mixture is proportional to its mole fraction present. The mole fraction, X, is the moles of a substance divided by the total moles present.

Total moles present = 0.55 + 0.94 + 0.35 = 1.84

P(He) = X(He) x P(total) = (0.55/1.84) x 0.80 atm = 0.24 atm He

P(Ne) = X(Ne) x P(total) = (0.94/1.84)  x 0.80 atm = 0.41 atm Ne

P(Ar) = X(Ar) x P(total) = (0.35/1.84) x 0.80 atm = 0.15 atm Ar