A mixture of gases contains CH4,C2H6, and C3H8?

Question

if the total pressure is 1.50atm and the numbers of moles of the gases present are 0.31 mole for CH4,0.25 mole for C2H6,and 0.29mole for C3H8,calculate the partial pressures of the gases.

Answer 1

Ptotal = PCH4 + PC2H6 + PC3H8

Pgas= (xgas)(Ptotal)

xgas is the mole fraction of a gas

PCH4= [0.31 / (0.31 +0.25 + 0.29)] X Ptotal

PC2H6 = [0.25 / (0.31 +0.25 + 0.29)] X Ptotal

PC3H8 = [0.29 / (0.31 + 0.25 + 0.29)] X Ptotal

no calculator here. ill leave it up to you here on.