Question:

A motorboat travels 36km downstream in 2 hrs. In coming back upstream the trip takes 3 hrs. ?

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Find the rate of the boat in still water and the rate of the current?

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  1. let b = speed of boat in still water

         c = speed of current

    remember... distance = rate x time (d = rt)

    going downstream:

    the boat travels 36 km, so d = 36

    took 2 hours, so t = 2

    since the current is helping your speed, r = b + c

    so you have an equation:

    36 = 2(b+c)

    going upstream:

    the boat travels 36 km, so d = 36

    took 3 hours, so t = 3

    since the current is NOT helping your speed, r = b - c

    so you have an equation:

    36 = 3(b-c)

    you have two equations and two variables... now either use substitution or elimination to find that b = 15 km/hr and c = 3 km/hr.


  2. We use the formula distance = rate * time. Let b = rate of the boat and c be the rate of the current. Then:

    36 = 2(b + c)

    36 = 3(b - c)

    Simplify both equations and add together:

    18 = b + c

    12 = b - c

    -----------------

    30 = 2b

    b = 15

    18 = b + c

    18 = 15 + c

    c = 3

    The boat travels at 15 km/h and the current is 3 km/h.

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