A parachutist with a camera, both descending at a speed of 10 m/s, releases that camera at an altitude of 50m?

Question

How long does the camera take to reach the ground? What is the velocity of the camera just before it hits the ground?

Answer 1

vf= final velocity

vo = initial velocity = 10 m/s

g= 9.81m/s^2

s= distance= 50 m

vf^2 = vo^2 +2gs

vf= √(vo^2 +2gs)

vf= 32.9 m/s

vf = vo + gt

t= (vf- vo)/g

t=2.33 s

or  

s= 0.5gt^2+vot

0 =0.5gt^2+vot -s

solve for roots t =2.33