A physics question....plz help?

Question

if a bowling ball traveling with constant speed hits the pin at the end of a bowling lane 16.5m long. the bowler hears the sound of the ball hitting the pins 2.50s after the ball is released from his hands. what is the speed of the ball? the speed of sound is 340m/s.

Answer 1

total time from release of ball to sound

coming back to ear:

2.5 seconds

time for sound wave to travel up the alley:

16.5 m / 340 (m/s) = 0.04852 seconds

time for ball to go down the alley:

=(total time)-(time sound wave) back to ear:

2.5 - 0.049 = 2.451 seconds

speed of ball

v= d/t = 16.5/2.451

=6.732 m/s

Answer 2

here you have:

total time until the bowler hears the sound = time of ball traveling down the lane + speed of sound after collision

you are told that the total time is 2.5s, and the time for the sound to reach the bowler is t=16.5 m/340 m/s = 0.0485 s

thus, the time the ball took to travel down the lane is 2.5-0.0485=2.45s

the speed of the ball is then speed = 16.5m/2.45s=6.73 m/s

Answer 3

16.5 / 2.5 = 6.6 m/s

The sound delay at that distance is negligible.

Answer 4

About 6.733 m/sec

Answer 5

Your working equations are as follows:

S = V(Tb) or V = S/Tb  --- call this Equation 1

S = 340(Ts) --- call this Equation 2

where

S = length of the bowling alley

V = speed of the bowling ball

Tb = time for bowling ball to hit the pins after being thrown

Ts = time for sound to travel back to the bowler after pins are hit

NOTE that Tb + Ts = 2.5

or Ts = 2.5 - Tb and substituting this into Equation 2,

S = 340(2.5 - Tb) or solving for "Tb"

Tb = 2.5 -  S/340 = 2.5 - 16.5/340

Tb = 2.45 sec.

Substitute this calculated value of "Tb" into Equation 1,

V = 16.5/2.45

V = 6.73 m/sec.

Hope this helps.