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A population (normal) of disks has a mean life of 40 hours and a standard deviatin of 6?

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A population (normal) of disks has a mean life of 40 hours and a standard deviatin of 6

hours. Let X = life of a disk.

If a disk is sampled find: prob (X< = 30)

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  1. z = (30 - 40)/6 ≈ - 1.67

    P(X ≤ 30) ≈ P(z ≤ - 1.67) ≈

    0.5000 - 0.4525 ≈ 0.0475

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