A problem with birthdays?

Question

You have 24 people in a room. What is the probability that at least 2 of them will share the same birthday? Although not necessarily the same year?

Answer 1

The answer is approx a half... the explaination is rather complicated, so check out this page for a decent explaination - http://en.wikipedia.org/wiki/Birthday_pa...

Answer 2

whatever the probabilty .. cant be bothered to work it out (hate maths)

it doesnt matter about whether there birthday is as you put it "not necessarily the same year" because someones birthday is the same date every year so if two people have the same birthday the year doesnt count ... is this some kinda trick question or something.

Answer 3

24 people can be arranged in 24! ways. There are 24C2 combinations of two people.

So I think the probability will be 24C2 / 24!

Answer 4

P(at least 2 have same bday)

= 1 - P(none have the same bday)

= 1 - (365/365)(364/365)(363/365)...(342/365)

= 0.54 (2 d.p.)

Answer 5

The odds of sharing a birthday with somebody are 13-1 so if there are 24 people there at least 2 should theoretically share a birthday.

Answer 6

I used to be good at this. maybe I should pick up my maths book again. good thing I kept it!

Answer 7

It's something weird like 50% I think...I didn't believe it at first but i guess it make sense really

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