A rectangular fence twice as long as it is wide with area of 6,050 Jan needs 1 fence pole every 7ft. of fenc?

Question

how many poles are needed?

Answer 1

let w be width; then 2w is length  and area = 2w^2 = 6050

w^2 = 3025 and sad person that I am, I know the square root of this is 55 ft.  So dimensions are 55 by 110 ft.(NB I assume it means a fence round a rectangular area)

However, neither of these is exactly divisible by 7 and of course it is rectangular so needs a post at each corner.  I will assume that is an extra post.

the 110 length divided by 7 gives 15 remainder 5 - that needs to be rounded up to 16 sections of 7, but as the post needs to be at each end, 17 posts.  Another 17 posts for the other long side.

Now, the shorter sides already have posts at either end (ie the ends of the longer sections) and there are just under 8 7ft sections in 55 ft. So we need 7 posts for each of the two shorter sides.  48 posts.

Answer 2

Still trying to get those Penn Foster answers are you? With all the time it takes you to make new accounts and type out the problem, why not just look up the answer?

Answer 3

7,890,345,234,890,222,456