A rigid container of O2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?

Question

Hi. I am stuck on this question. Thanks!

Answer 1

340 x 273/713, which is roughly one bar.

Answer 2

As the container is rigid the volume doesn't change, so, if we use the ideal-s gas equation we have that>

PV=nRT (V and n are constants)

For two situations, let's call them #1 and #2>

P1/T1 = P2/T2

So, the pressure at 273K would be:

P2 = P1T2/T1 = 340 x 273 / 713 = 130.18 KPa = 1.31 bar