Question:

A small area in front of a building is triangular in shape.

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The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region.

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  1. The given parameters are:

    a=first side

    b=second side

    c=third side

    a+b+c=37meters

    b=a/2

    c=a-3

    Therefore:

    a+(a/2)+(a-3)=37

    Solve for a=16meters

    Substitute back into b and c to get:

    b=8 meters

    c=13 meters

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