Question:

A small first aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s....?

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after 2.5 s, what is the velocity of the first aid kid and how far is the kit below the climber?

please help:)

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  1. The velocity of the climber is kind of irrelevant since all objects in freefall travel at a velocity of 32 feet per second/per second.  In other words, its initial velocity is 32ft./s and it accelerates by 32f/s every second.


  2. Well in 2.5s the kit (ignoring air resistance) will be traveling at 2.5s  x 9.8 m/s^2 = 24.5m/s faster than when it was dropped, since it was going 1.3 m/s at the start, the velocity will be 25.8m/s

    It's average speed for those 2.5s will be 24.5/2 + 1.3 = 13.55m/s

    13.55m/s  times 2.5s = 33.88 meters below the point at which it was dropped, however the climber has descended 2.5s x 1.3m/s = 3.25 meters so the distance from the climber is 30.6m (the speed of the climber is NOT irrelevant)

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