A solid cylinder of radius R = 1.0 m and mass 10 kg rotates about its axis. When its angular velocity is 10 ra

Question

A solid cylinder of radius R = 1.0 m and mass 10 kg rotates about its axis. When its angular velocity is 10 rad/s, its angular momentum (in kg × m2/s) is

50.

20.

40.

25.

70.

Answer 1

H = I * ω

where,

H = Angular Momentum

I = Moment of Inertia

ω = Angular Velocity (10 rad/s)

The moment of inertia for a cylinder rotating about an axis that goes through the center of the two circular faces is:

I = (1/2) * m * r²

=> I = (1/2) * (10 kg) * (1.0 m)²

=> I = 5 kg*m²

So angular momentum,

H = (5 kg*m²) * (10 rad/s)

=> H = 50 kg*m²/s

Therefore, the angular momentum of the cylinder is: 50 kg*m²/s.