A stone is thrown vertically downwards with a velocity of 12m/s. How far does it travel in 10s.

Question

A stone is thrown vertically downwards with a velocity of 12m/s. How far does it travel in 10s.

Answer 1

just look up the kinematics equations

d = vit + .5at^2

d= 12m/s(10s) + (0.5)(9.8m/s^2)(100s^2) = 120 m + 490m =610m

Answer 2

Given:

Vi = 12 m/s

g = 9.8 m/s^2

t = 10 s

Find:

d = distance the stone traveled in 10 s

Solution:

d = Vi(t) + (1/2)(g)(t^2)

d = (12 m/s)(10 s) + (1/2)(9.8 m/s^2)(10 s)^2

d = 610 m     ANSWER

Hope this helps.

teddy boy

Answer 3

S=ut+1/2gt^2  S=12*10+1/2*10*10^2   S=120+0.5*10*100

S=120+500

S=620m

Answer 4

12m/s times 10s. The two s cancel eachother out (12m *10s)/s. so it becomes 12m*10 = 120m