A straw has a radiu of 0.13 inch and a lengh of 7 inches. how much material was used to make the straw?

Question

round your answer to the nearest tenth please?

Answer 1

*What is the straw material?

I am considering 0.13 inch as a OR.

I am considering 0.01 inch as a thickness.

Weight = volume*density

Volume=0.7854*length*[OD^2 - ID^2 ]

Volume=3.1416*length*[OR^2 - IR^2 ]

Volume=3.1416*length*THICKNESS*[OR + IR ]

Volume=3.1416*7.0*0.01*[0.13 + 0.11 ]

Volume=0.219912*0.24

Volume=0.05277888 inch^3

Weight = volume*density [suppose density is "X", then

Weight =0.05277888 *X  Lbs.

Answer 2

You need to use better terminology. "how much material" is vague, but appears to mean volume.

As another answer said, you need the ID to calculate volume.

.

Answer 3

2 * pi(3.14) * r * h

area comes 44 sq inches. For the volume,u need to know the inner radius.

Answer 4

How thick is the wall of the straw?

The volume of a cylinder is πr²h

where h is the height and r is the radius

To compute the material used to make a straw we need to know the inside and outside radius of the straw.  (Basically the thickness of the walls of the straw)

If we assume the outside radius is R and the inside radius is r, then we can compute the material used by "subtracting out" the volume of the inside cylinder.  (The hollow part)

Volume = πR²h - πr²h

Using algebra to simplify the equation:

Volume = πh(R² - r²)