Question:

A student prepared aspirin in a laboratory experiment using the following reaction.?

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C7H6O3 + C4H6O3 = C9H8O4 + HC2H3O2

salicylic acid acetic anhydride aspirin

The student reacted 1.75 g salicylic acid with 2.33 g acetic anhydride. The yield was 1.75 g aspirin. Calculate the theoretical yield for this experiment.

theoretical yield

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  1. Great Question

    So you would need to find out the molecular mass of a couple of things:

    Salicylic Acid = 138.123g/mol

    Acetylsalicylic Acid (Asprin) = 180.160g/mol

    The reaction is a 1:1 mole ratio

    ~~~~~~~~1 mol~~~~~~1 mol~~180.160 g

    1.75 g x _______--x---_____-x--__________= 2.28g (theoretical)

    ~~~~~~~138.123g~~~~1 mol~~~1 mol~~~

    Your theoretical yield is 2.28 g of Acetylsalicylic Acid (Asprin)


  2. First, determine the number of moles of your reactants (i.e. salicylic acid and acetic anhydride)

    given from the molecular formula:

    MW salicylic = 138 g/mole

    MW acetic anhydride = 102 g/mole

    MW aspirin = 180 g/mole

    moles of salicylic acid = 1.75 g / 138 g/mole = 0.0127 moles

    moles of acetic anhydride = 2.33 g / 102 g/mole = 0.0228 moles

    since the reaction is 1:1 ratio...then the number of moles of least value, which is the salicylic acid will be converted to aspirin...therefore

    moles of salicylic acid = moles of aspirin (since the ratio is 1:1)

    to determine the grams of aspirin:

    g of aspirin = moles of aspirin x MW of aspirin

    g of aspirin = 0.127 moles x 180 g/mole = 2.28 g is the theoretical yield

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