A subatomic particle travels at a velocity of 2.0*10^10 cm/sec. What is its velocity in meters/hour?

Question

please show work

Answer 1

1 m = 100 cm

First, divide by 100 to get the units in meters/sec.

(2 x 10^10 cm/sec)*(1 m/100 cm) = 2 x 10^8 m/sec

1 min = 60 seconds

60 min = 1 hour

Therefore, 1 hour has 3600 seconds.

(2 x 10^8 m/sec)*(3600 sec/hour)  = 7.2 x 10^11 m/hr

:)

Answer 2

2*10^10 cm/sec = 2*10^8*10^2 cm/sec = 2*10^8 m/sec = 2*10^8*3600 m/3600 sec = 2*10^8*36*10^2 m/h = 72*10^10 m/h

Answer 3

2.0*10^10 cm | 60 sec | 60 min | 1 m

--------------------------------------...  = ...

sec      | 1 min  |  1 hr    |  100 cm

Take the numbers above the line, multiply them together, then divide them by the numbers below the line.  If you notice, the units cancel out, giving meters/ hour.  I gave you the work.  Sorry, my calculator is giving me grief.  I do hope you can solve it from here.

Answer 4

Before we do any work we need to determine our conversion factors.

we want to express distance in meters and in order to do that we must convert from centimeters to meters.

1 inch = 2.54 centimeters and 1 meter = 39.37 inches or you could just notice that there is 1 meter for very 100 centimeters

we also need to convert our units of time from seconds to hours. This should be easy:

1 minute = 60 seconds and there is 1 hour in 60 minutes

.

so

(2.0 x 10^10 cm/sec)(1 inch/2.54 cm)(1 m/39.37 in)(60 sec/1 min)(i hour/60 min) = 7.2 x 10^11 m/hr

The only trick to these types of problems is to know the conversion factors and then to manipulate them in such a way as to cancel out the factors you don't want to express.

Answer 5

2.0*10^10cm/sec  X  1m/100cm    X    60sec/1 min   X    60 min/1 hr