A supporting wire is to be attached to the top of a 46-foot antenna.?

Question

If the wire must be anchored 46 feet from the base of the antenna, what length of wire is required?

Answer 1

46*√(2) or 65.05 feet

Answer 2

a^2 + b^2 = c^2

(46ft height)^2 + (46ft out distance)^2 = c^2

46^2 + 46^2 = 4232

4232 = c^2

c = sqrt(4232)

   = ~ 65.053823 ft

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Of course, I assumed it was a 46ft HIGH antenna!!  It might have also been a 46ft horizontal antenna.  In that case, you don't have the height at all.  So, it's assumed it is a 46ft high monopole, sticking straight up.