Question:

A thin wire is bent into the shape of a semi-circle x^2 + y^2 = 9 (x greater than or equal to 0)?

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If the linear density is a constant 'k', find the mass of the wire.

a) 3kπ

b) 9kπ

c) 6kπ

d) kπ

e) (kπ)/6

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  1. x^2 + y^2 = 9

    Or, x^2 + y^2 = 3^2

    Therefore radius r = 3

    Perimeter of full circle = 2πr

    The wire is in the shape of a semi-circle. Therefore lengths of wire = 2πr/2 = πr = 3π

    Mass = length * linear density = 3π * k = 3kπ

    Ans: (a)

    AI P has used full circle instead of semi-circle.


  2. changing circle to semi-circle

    r=3

    c=2*pi*r=2*pi*3

    mass=6*k*pi

    answer: c)

    if semi-circle radius=3

    length=pi*3

    mass=3*k*pi

    answer: a)

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