A train goes forward at a speed of 1m/s for 20 seconds.then it stops and goes backward at a speed of 0.5 m/s?

Question

for 4 second.after both movements are completed how far is the train located m its starting point .note:i am asking for the train's final location not the total distance that it traveled

Answer 1

No idea.  This is a math problem. Go ask in the math section.

And take the metric system with you!

Answer 2

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Answer 3

forward = 1 X 20 = 20m

backward = -0.5 X 4 = -2m

total displacement = +18m

Answer 4

for the first part, when the train is traveling forward:

the train moves at 1m/s, which means every second it will travel 1 meter, so in 20s it will move to 20m

when the train is moving back, it moves 0.5m/s for 4 seconds, which means it will travel half meter (0.5m) in 1 second, so it will travel 0.5x4 = 2m in 4 seconds

so the distance traveled is, 20m forward and 2m backwards. 20-2 = 18m is the final location from the starting point