A volcano launches a lava bomb at 28m/s. find speed of lava bomb after 2.0 seconds and after 3.0 seconds?

Question

A volcano launches a lava bomb at 28m/s. find speed of lava bomb after 2.0 seconds and after 3.0 seconds?

Answer 1

Assuming that the lava bomb is projected straight up into the air (since you didn't specifiy an angle), the velocity at time t will be

v(t)= -9.8*t+ v0,

where -9.8m/s^2 is downward gravitational acceleration,

and v0 is the initial velocity, 28.0 m/s

so plug in 2m/s and 3m/s for t, and you have your answers:

v(2) = 8.4 m/s (still moving upward because sign is positive)

v(3) = -1.4 m/s (moving downward because sign is negative)