A wire of resistance 2 ohm is connected to a source of 50 volts at its two ends. what is the current in wire

Question

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Answer 1

acc 2 ohms law u cn calculate i=v/r.so it is 25amps

Answer 2

   V=R*I

   I=V/R

   V=50v , R=2Ohm

    so that

         I=V/R  =50/2

         I=25Amp

    

Answer 3

50/2=25amp

Answer 4

    Ohms law: V=iR

                    

                     50=i(2)

                    i=25amp

Answer 5

Ohm's Law:

I=V/R

I=50/2 = 25 amps.

If the source is a normal accumulator, it must have capacity to deliver such high amperes. If not, the value of 25 amps is only theoretical.

This example also shows that it is dangerous to connect any wire across the terminals of a voltage source.  

Answer 6

r = 2; v=50

v = ir ; i = v/r = 50/2 = 25

therefore, current is 25amp

Answer 7

I=V/R <--Ohms Law.

Current is 25 amps.

Answer 8

according to ohm's law V(voltage) is propotional to I(current) so V=IR,where R is the resistance.so in this case R=2 and V=50 so I=50/2=25 ampere

Answer 9

Acc to ohms law,at constant temperature,the voltage across a conductor is directly proportional to the current flowing through it.

V=IR

R=resistance

As  R=2  ohm

      V=50  volts

therefore i= V/R

              i=  50/2 = 25  amperes.