AB is chard of a circle of radius 6.0m which subtends an angle of 120^o at the C.

Question

How do i find the length of the minor arc AB , the area of the triangle ACB , and the area of the minor sector CAB

Answer 1

Area of sector = R^2 * a / 2

R = 6 meters

a = 120 degrees

Area of triangle = Area of sector - ((R^2 / 2)*(pi*a/180 - sin(a) )

which is the area of the sector - the area of the segment

Arc length =  2 * R * pi * a/360

1/3 of the circumference in this case -- 120/360 = 1/3

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