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A rock is thrown nearly straight upward from the edge of the top of a building at an initial speed of 16.0 m/s. Its trajectory will take it just past the edge, so that it lands on the ground. How much later must a second rock be dropped from rest at the same initial height of 14.1 m so that the two rocks hit the ground at the same time? I've gotten this far:The second rock will take 1.7sec after it is dropped to hit the groundThe first rock will reach its maximum height at 13.06m after 1.632secBut how do I make this all come together?
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