Question:

According to the following equation.How many grams of O2 are required to burn 3.01 x 1023 propane molecules?

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Propane (C3H8) burns in oxygen to form CO2 and H2O according to the following equation. How many grams of O2 are required to burn 3.01 x 1023 propane molecules?

C3H8 + 5O2>>>3CO2 + 4H2O

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  1. Actually

    Use Avogadro's law to find the number of moles of propane.

    multiply by 5 (make sure you understand why) to find moles O2.

    Finally, multiply moles O2 by the relative molar mass of O2 to get grams O2.

    Hint: in ALL these problems where you go from one substance to another, you go by way of moles, and use the balanced equation to give you the conversion factor (just like an exchange rate when you're changing money) between moles of different substances.


  2. 3.01*10^23molecules is 0.5 mole

    you see you need 5 molesO2 for 1 mole C3H8 (propane annon butane)

    so you need 5*0.5= 2.5 moles of O2

    in grams 2.5*32=80g O2

  3. 5*32*0.5

    0.5 is the number of moles of propane you have to burn

  4. Use Avogadro's Number to find the number of moles of propane.

    multiply by 5 (make sure you understand why) to find moles O2.

    Finally, multiply moles O2 by the relative molar mass of O2 to get grams O2.

    Hint: in ALL these problems where you go from one substance to another, you go by way of moles, and use the balanced equation to give you the conversion factor (just like an exchange rate when you're changing money) between moles of different substances.

  5. Your equation tells you that 1mol C3H8 requires 5mol O2

    You want to burn 0.5mol C3H8 (ref Avagadro)

    Therefore you will require 2.5mol O2

    Molar mass O2 = 32g

    2.5 mol O2 = 32*2.5 = 80grams.O2 required

  6. I will assume you mean 3.01 X 10^23 molecules. = 0.5 moles

    1 mole of propane molecules needs 5 moles of O2 molecules.

    0.5 moles of propane needs 2.5 moles of O2.

    Now mass of 1 mole of O2 = 16X2 = 32 g

    Therefore mass of O2 needed = 32X2.5 = 80 g = Ans

  7. mol C3H8 = 3.01x10^23/NA = 0.5mol

    molO2 = 5*molC3H8 = 2.5mol

    gO2=2.5*32=80g

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