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Add and subtract as indicated.b/b-1 2b/b^2-1,a-1/a 1 a 1/a-1,4/a-5-1/5-a

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Add and subtract as indicated.b/b-1 2b/b^2-1,a-1/a 1 a 1/a-1,4/a-5-1/5-a

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  1. ok do you want the answer


  2. I think you should ask this in the science and math section

  3. 1.  b/(b-1) + 2b/(b^2-1)

    = b/(b-1) + 2b/[(b-1)(b+1)]

    = b(b+1)/[(b-1)(b+1)] + 2b/[(b-1)(b+1)]

    = (b^2 +b +2b)/[(b-1)(b+1)]

    = (b^2+3b)/[(b-1)(b+1)]

    2.  (a-1)/(a+1) + (a+1)/(a-1)

    = (a-1)(a-1)/[(a-1)(a+1)] + (a+1)(a+1)/[(a-1)(a+1)]

    = (a^2 -2a+1 +a^2+2a+1)/[(a-1)(a+1)]

    = (2a^2+2)/[(a-1)(a+1)]

    = 2(a^2+1)/[(a-1)(a+1)]

    I'll let you do the last one.

    Did you notice how I put parentheses around the numerators (top part of fraction) and the denominators (bottom part of fraction)?  Please use parentheses next time.

    Here's a hint for the last one:  Notice that 5-a = -1(a-5).

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