Algebra 1 help ! simplifying ?

Question

Explain the steps needed to simplify

6

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sqrt of 3 + sqrt of 19

if you could please explain how to do this to me ? i really do not undertsand it

xo rose

god bless you

thank you.

Answer 1

Step 1: Simplify the denominator

6 / (SQRT 3 + SQRT 19) =

6 / (SQRT 22) or 6 / (22)^1/2

Step 2: Remove the SQRT from the denominator

(6* SQRT 22) / (SQRT 22 * SQRT 22)

or re-written

(6 * 22 ^ 1/2) / (22^1/2 * 22^1/2)

Step 3: Add Like Power

(6 * SQRT 22) / (22 ^ 1/2 + 1/2)

Step 4: Simplify

6 * (SQRT 22) / 22 ^1

Or

6 * (SQRT 22) / 22

Answer 2

That is a very easy question.

What is the square root of 9? 3.

So its 6 over the square root of 3 times 3.

Now what is 6/3? 2.

So the answer is 2 square root of 3.