Algebra 1 questions? Please Help!?

Question

Use the nth term to list the first five terms of each sequence. Show all your work.

An=10n

an=1/2n

an=n+8

an=14-n

an=4n-3

an=3n+1

Answer 1

The first term is when n = 1, the second is when n = 2 and so on until the fifth term is when n = 5.  So, let n be each of these values to find the first five terms in the sequence.  

An = 10n

1st term = 10*1 = 10

2nd term = 10*2 = 20

3rd term = 10*3 = 30

4th term = 10*4 = 40

5th term = 10*5 = 50

An = (1/2)n

1st tem = (1/2)*1 = 1/2

2nd term = (1/2)*2 = 1

3rd term = (1/2)*3 = 3/2

4th term = (1/2)*4 = 2

5th term = (1/2)*5 = 5/2

An = n + 8

1st tem = 1 + 8 = 9

2nd term = 2 + 8 = 10

3rd term = 3 + 8 = 11

4th term = 4 + 8 = 12

5th term = 5 + 8 = 13

An = 14 - n

1st tem = 14 - 1 = 13

2nd term = 14 - 2 = 12

3rd term = 14 - 3 = 11

4th term = 14 - 4 = 10

5th term = 14 - 5 = 9

An = 4n - 3

1st tem = 4*1 - 3 = 1

2nd term = 4*2 - 3 = 5

3rd term = 4*3 - 3 = 9

4th term = 4*4 - 3 = 13

5th term = 4*5 - 3 = 17

An = 3n + 1

1st tem = 3*1 + 1 = 4

2nd term = 3*2 + 1 = 7

3rd term = 3*3 + 1 = 10

4th term = 3*4 + 1 = 13

5th term = 3*5 + 1 = 16

Hope this helps you!

Answer 2

Plug 1,2,3,4,5 into each problem

an=10n

a(1)=10

a(2)=20

a(3)=30

a(4)=40

a(5)=50

1) So the sequence is

10,20,30,40,50...

The rest i will do in my head but its the same idea.

2) 5, 2.5, 1.25,. 75, .375...

3) 9,10,11,12,13...

4) 13,12,11,10,9...

5) 1,5,9,13,17...

6) 4,7,10,13,16...

Hope that helps